To produce 196.5 g of aluminum sulfate, what m of aluminum must react with sulfuric acid?

The formula of aluminum sulfate is Al2(SO4)3. You need to add up all the mes from the periodic table. 2 Al = 2(27) = 54, 3 S = 3(32) = 96 12 O = 12 (16) = 192 Add all of those. 54+96+192= 342. What part is due to Al? 54gAl for every 342g of Al(SO4)3. If you multiply this ratio by the amount of aluminum sulfate in your problem, then you would know how much Al you will need to react. 196.5g x (54g/342g) = 31.03g Al